The quixotic team trying to build a world in a 20-year-old game

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count[idx]--; // 该值的可用位置-1

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If this sounds familiar to you, it’s because this method works very similarly to error-diffusion. Instead of letting adjacent pixels compensate for the error, we’re letting each successive candidate compensate for the combined error of all previous candidates.

if (!FuncPtrOut)

A01头版